Coco Gauff succeeded in the Montreal tournament by having his compatriot Danielle Collins in three sets. It also goes for Elena Rybakina in two rounds against Hailey Baptiste.
Winner at Roland-Garros this year, Coco Gauff has experienced a hard return to reality since. Eliminated in the first round in Berlin, then in Wimbledon, the world number two returned to the hard-year-old on the occasion of the start of the North American tour. And for her entry into Montreal, it was Danielle Collins, specialist in the surface that stood on her way. A duel of Americans, who almost turned to the advantage of the 61st world player. Especially with the 23 double faults committed by GAUFF. Yes, 23! If Collins did 13, she managed to equalize a set everywhere after the loss of the first set. A first round off with seven breaks, which was running in favor of Gauff (7-5).
Winner of Tomova in the first round, Collins first put back his break behind in the second set (3-1) before finally pocket the Channel (4-6). Then Gauff trembled. While led 4-2, then 5-4, she saw Collins return and serve for the match at 6-5. No match ball to put themselves under the tooth and a tie-break that was going to decide the winner in an undecided match. After 2h56 of combat, Gauff won the tie-break (7-5, 4-6, 7-6 (2)) and will face Veronika Kudermetova in the next round. In total, Gauff and Collins will have conceded 16 break balls each.
Rybakina won against Baptiste
We had left Elena Rybakina on a defeat in the semi-finals of Washington. We found the smiling kazakh in Montreal. For its entry into the tournament, the seeded 9 has had an American, Hailey Baptiste. A round never obvious against the powerful 50th world player, which Rybakina has nevertheless mastered. With 11 aices in the game and 84 % points won behind her first ball, the world world has never trembled, saving the three break balls she conceded.
It was enough for him a white break to afford the first set (6-4), before breaking again in the middle of the second round (4-2) the American. By concretizing the two unique match balls of the match, Rybakina made 100 % and will find the Romanian Jaqueline Cristian in the next round.
Kenin and Haddad Maia eliminated
Selected 23 of the tournament, Sofia Kenin underwent the law of the local Victoria Mboko. The 18-year-old Canadian, who will celebrate her 19 candles on August 26, dominated the Australian 2020 Open winner in two rounds (6-2, 6-3). Impressive at the service with 12 Aces, Mboko has never doubted and will face the Czech Marie Bouzkova in the next round. Finally, the Brazilian Beatriz Haddad Maia sold in three rounds against the Dutch Suzan Lamens (6-2, 1-6, 6-3).
